How do I figure out how many moles of solid to add to increase ions in solution?

How many moles of solid Ba(NO3)2 should be added to 300mL of 0.2M Fe(NO3)3 to increase the concentration of the NO3- ion to 1M? (assuming that the vol of the soltn remains the same)





How should I approach this problem? Thanks.How do I figure out how many moles of solid to add to increase ions in solution?
Moles Fe(NO3)3 = 300 x 0.2 /1000 = 0.06





Moles NO3- = 0.06 x 3 = 0.18





M = moles / L





moles = M x L = 1 x 0.300 = 0.300





we have 0.18 moles NO3- so we add 0.300 - 0.18 = 0.12 mole NO3-





Ba(NO3)2 %26gt;%26gt; Ba2+ + 2NO3-





we need 0.12 /2 = 0.06 mole Ba(NO3)2

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